Originally Posted by
whizzer
This is true. As mentioned before, decibels are measures of relative power levels, so doubling the input power from 1 watt to 2 watts is a 3 dB increase, and so is the difference between 250 and 500 watts. However, doubling the input power does not double the acoustic energy produced by the loudspeaker. Adding a second identical system also receiving the same level of input signal would produce an actual doubling of energy--more in cases of acoustic coupling, as when assymetric folded horn mouths are arranged in mirror-imaged pairs. Simply applying a 3 dB increase in input power will not produce this magnitude of effect.
Nor are decibels absolute measures of sound level. John L. Murphy, of the True Audio Loudspeaker Design Center, states that if a loudspeaker were 100% efficient, an electrical input of 1 watt would produce an output of 1 acoustic watt, which, measured at 1 meter, would be 112.1 dB SPL (radiating into half space). The question ought to be, "112.1 dB above what?" The baseline level cannot be silence, for any multiple of no sound is still no sound. If we use the measurement of one loudspeaker's output that is produced by a 1 watt electrical input and, for instance, call it 85 dB, then how many times can we double the acoustic energy produced by that loudspeaker before it becomes burned out junk? If, on the other hand, if we measure the output of a system the same way, using the same equipment, and find a reading of 95 dB, we may double that acoustic energy perhaps the same number of times before destroying the transducer, but the ultimate output will be much greater. Now, obviously, either system will play softly enough to produce sounds that are barely audible, but the more efficient one will play far more loudly, thus its dynamic range is wider. Finally, listening to music at the same average level, the more efficient system with the wider dynamic range will, by allowing the amplifier greater reserves for reproducing transient peaks, simply sound "more dynamic."