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Thread: 4355

  1. #1
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    4355

    Hello forum

    Iīve read most of the 4350, 4635 threads, but canīt find anywhere the length of the ports of the 4355. Iīm trying to build a pair, but this one is missing. Please help me.
    Thanks, Gunther

  2. #2
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    Sorry for my confuse, I mean the length of the ports of the 4355.

  3. #3
    Administrator Mr. Widget's Avatar
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    I am sorry, I don't know what the actual port length is, but realize that they are curved and not simple straight lengths of tube, so you would want to trim them to the final length to achieve the desired resonant frequency. Having a curved tube complicates the math significantly.

    If you do not know how to measure tuning frequency do some google searches, it is fairly simple. The desired frequency is somewhere between 30 and 35Hz... I imagine the actual target frequency is posted here somewhere if you search our site...


    Widget

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    Thank you Mr. Widget
    Regards, Gunther

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    I think it's easy (if I am not wrong :)

    Quote Originally Posted by Mr. Widget View Post
    ... Having a curved tube complicates the math significantly. ...
    Widget
    The mass in the tube without any end corrections can easily be estimated, it's the same as that of a straight tube:

    1.) The volume of a torus (ring) is 2 x pi**2 x R x r**2 (complicated calculation, see Wikipedia)

    2.) The area of the torus cross section is r**2 x pi (easy)
    3.) The "length" of the torus (wrong word, I know) is 2 x R x pi (easy)

    "2" x "3" = "1 (easy calculation supplies proper result).

    Finally add the end corrections, as for a straight tube.

    Ruediger

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    Senior Member BMWCCA's Avatar
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    Quote Originally Posted by Ruediger in Ingolstadt View Post
    The volume of a torus (ring) is 2 x pi**2 x R x r**2...
    Do you design intake manifolds for Audi in your spare time?
    ". . . as you have no doubt noticed, no one told the 4345 that it can't work correctly so it does anyway."—Greg Timbers

  7. #7
    Administrator Mr. Widget's Avatar
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    Quote Originally Posted by Ruediger View Post
    "2" x "3" = "1 (easy calculation supplies proper result).
    "3"...i.e. length is the tricky part.

    Widget
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    It's simple!

    Quote Originally Posted by Mr. Widget View Post
    "3"...i.e. length is the tricky part.

    Widget
    I don't think so. In the calculations "R" is (inner radius + outer radius) / 2, and the length is that of a circle or part of a circle. I thought it was more complicated, but it is not.

    Try it this way: take the complicated formula for the volume of a torus. That is the result of a proper integration. Now consider that as cross "section x length". Divide it by the cross section of the torus. What remains is the length, and that leads You to the radius.

    Ruediger

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    Administrator Mr. Widget's Avatar
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    Quote Originally Posted by Ruediger View Post
    I don't think so. In the calculations "R" is (inner radius + outer radius) / 2, and the length is that of a circle or part of a circle. I thought it was more complicated, but it is not.

    The air in the tue shall behave like a lumped mass, all dimensions must be small when compared to the wavelength.

    Ruediger
    I get that, and I suppose the drawing is confusing my point. I am not sure that the port is based on an actual radius. From what I have seen it appears to be a slightly accelerated curve.


    Widget

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    Quote Originally Posted by Mr. Widget View Post
    I get that, and I suppose the drawing is confusing my point. I am not sure that the port is based on an actual radius. From what I have seen it appears to be a slightly accelerated curve.


    Widget
    Okay, then estimate how an equivalent port with a proper part of a torus would look like, and take the dimensions of that fictive (imagined) tube. length = (inner length + outer length) / 2.

    It's all estimates, as You know Yourself: the end corrections are, the assumption of a certain temperature (speed of sound), the assumption of a certain DC resistance of the voice coil.
    Last edited by Ruediger; 03-04-2011 at 11:50 PM. Reason: added "formula" for length

  11. #11
    Administrator Mr. Widget's Avatar
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    Quote Originally Posted by Ruediger View Post
    It's all estimates, as You know....


    That was basically my initial point... make the ports as close as you can by guessing and then measure the response to dial them in to the correct value. Calculations are great for determining the distance between galaxies, but sometimes working empirically is the best and easiest approach.


    Widget

  12. #12
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    Quote Originally Posted by hanad400 View Post
    Sorry for my confuse, I mean the length of the ports of the 4355.
    The I.D. is 5,1/4"

    The actual port is made up of 2 lengths of tube with mitred ends forming a angle not a curve.

  13. #13
    Senior Member Woody Banks's Avatar
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    Quote Originally Posted by John View Post
    The I.D. is 5,1/4"

    The actual port is made up of 2 lengths of tube with mitred ends forming a angle not a curve.
    Something like this?
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  14. #14
    Administrator Mr. Widget's Avatar
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    Quote Originally Posted by John View Post
    The I.D. is 5,1/4"

    The actual port is made up of 2 lengths of tube with mitred ends forming a angle not a curve.
    I don't remember them that way, but then I don't really remember much. Do you have a pair? In today's desire to avoid air turbulence, that wouldn't fly, but with such a large diameter, I am sure the acoustic compromise is minimal if at all.

    Widget

  15. #15
    Senior Member grumpy's Avatar
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    Something like this
    ?

    Interesting look, but I like them better mounted to the front baffle

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