Earl K
08-14-2003, 07:02 AM
Hi All
Originally posted by Giskard
Given a value for Fs of 35 Hz, Mms of 0.055 kilograms, and Sd of 0.090 square meters, Vas SHOULD be ~427.7 liters instead of 274.7.
This is given by:
Vas = (2 * pi * Fs)^2*Mms)^-1 * p0 * c^2 * Sd^2 * 10^3
Where Vas is in liters
Mms is in kilograms
p0 is 1.18 kilogram/cubic meter (mean density of air)
c is 345 meters/second (speed of sound)
Sd is in square meters
- I now have quite a few le14a & le10a with refurbished LansaLoy surrounds. The range of Fs is fairly broad ( 20 to 30 hz ) . I should derive new Vas figures for them. If I can avoid building a dedicated Vas test enclosure - then that's a route I'd like to examine.
- Does anyone know the origin/author of the above quoted Vas formula ?
- & How does it compare or correlate to deriving Vas from a test box ?
best regards <> Earl K
Originally posted by Giskard
Given a value for Fs of 35 Hz, Mms of 0.055 kilograms, and Sd of 0.090 square meters, Vas SHOULD be ~427.7 liters instead of 274.7.
This is given by:
Vas = (2 * pi * Fs)^2*Mms)^-1 * p0 * c^2 * Sd^2 * 10^3
Where Vas is in liters
Mms is in kilograms
p0 is 1.18 kilogram/cubic meter (mean density of air)
c is 345 meters/second (speed of sound)
Sd is in square meters
- I now have quite a few le14a & le10a with refurbished LansaLoy surrounds. The range of Fs is fairly broad ( 20 to 30 hz ) . I should derive new Vas figures for them. If I can avoid building a dedicated Vas test enclosure - then that's a route I'd like to examine.
- Does anyone know the origin/author of the above quoted Vas formula ?
- & How does it compare or correlate to deriving Vas from a test box ?
best regards <> Earl K